C语言实现推箱子项目

int map[13][14]={
 {0,0,0,0,1,1,1,1,1,1,0,0,0,0},
 {0,0,0,0,1,0,0,0,0,1,0,0,0,0},
 {0,1,1,1,1,0,0,4,4,1,1,1,1,1},
 {0,1,0,0,0,1,0,0,0,1,0,0,0,1},
 {0,1,0,4,0,0,0,4,0,0,0,4,0,1},
 {0,1,0,0,0,1,1,0,1,1,1,1,1,1},
 {1,1,1,1,4,1,1,0,0,0,0,0,0,1},
 {1,0,0,0,4,0,1,0,0,0,5,0,0,1},
 {1,0,4,0,4,0,1,0,1,1,1,1,1,1},
 {1,1,0,0,4,0,1,0,1,3,3,3,1,0},
 {0,1,0,1,1,0,0,0,0,3,3,3,1,0},
 {0,1,0,0,0,0,1,1,3,3,3,3,1,0},
 {0,1,1,1,1,1,1,1,1,1,1,1,1,0},
 };

void mape()
{

 int i,j;
 for(i=0;i<13;i++)
 {
 for(j=0;j<14;j++)
 {
 switch(map[i][j])
 {
 case 0:printf(" ");break;
 case 1:printf("■");break;
 case 3:printf("☆");break;
 case 4:printf("□");break;
 case 5:printf("♀");break;
 case 8:printf("♀");break;//人在目的地
 case 7:printf("□");break;//箱子在目的地
 }
 }
 printf("\n");
 }
 
}

void playgeme()
{
 char ch;
 int i,j;
 //找到人的坐标
 for(i=0;i<13;i++)
 {
 for(j=0;j<14;j++)
 {
 if(map[i][j]==5||map[i][j]==8)//人在空地和在终点两种情况
 break;
 }
 if(map[i][j]==5||map[i][j]==8)
 break;
 }
 printf("%d %d",i,j);//打印坐标
 ch=getch();//得到键盘值
 switch(ch)
 {
 //向上
 case 'W':
 case 'w':
 if(map[i-1][j]==0||map[i-1][j]==3)//下一个地方是空地或者目的地
 {
 //将人和空地或目的地交换
 map[i-1][j]+=5;
 map[i][j]-=5;
 
 }
 else if((map[i-1][j]==4||map[i-1][j]==7)&&(map[i-2][j]!=1)&&(map[i-2][j]!=4))//下一个地方是箱子并且箱子不靠近墙和箱子
 {
 map[i-2][j]+=4;//变箱子
 map[i-1][j]+=1;//变人
 map[i][j]-=5;//变空地
 
 }
 break;
 //向下
 case 'S':
 case 's':
 if(map[i+1][j]==0||map[i+1][j]==3)//下一个地方是空地或者目的地
 {
 //将人和空地或目的地交换
 map[i+1][j]+=5;
 map[i][j]-=5;
 
 }
 else if((map[i+1][j]==4||map[i+1][j]==7)&&(map[i+2][j]!=1)&&(map[i+2][j]!=4))//下一个地方是箱子并且箱子不靠近墙和箱子
 { 
  map[i+2][j]+=4;
  map[i+1][j]+=1;
  map[i][j]-=5;
 }
 break;
 //向左
 case 'A':
 case 'a':
 if(map[i][j-1]==0||map[i][j-1]==3)//下一个地方是空地或者目的地
 {
 //将人和空地或目的地交换
 map[i][j-1]+=5;
 map[i][j]-=5;
 
 }
 else if((map[i][j-1]==4||map[i][j-1]==7)&&(map[i][j-2]!=1)&&(map[j-2][j]!=4))//下一个地方是箱子并且箱子不靠近墙和箱子
 {
 
 map[i][j-2]+=4;//空地变成箱子
 map[i][j-1]+=1;//箱子变人
 map[i][j]-=5;//人变空地
 
 
 }
 break;
 //向右
 case 'd':
 case 'D':
 if(map[i][j+1]==0||map[i][j+1]==3)//下一个地方是空地或者目的地
 {
 //将人和空地或目的地交换
 map[i][j+1]+=5;
 map[i][j]-=5;
 }
 else if((map[i][j+1]==4||map[i][j+1]==7)&&(map[i][j+2]!=1)&&(map[i][j+2]!=4))//下一个地方是箱子并且箱子不靠近墙和箱子
 {
 
 map[i][j+2]+=4;//空地变箱子
 map[i][j+1]+=1;//箱子变人
 map[i][j]-=5;//人变空地
 
 }
 break;
 }
}