Django视图函数执行,不在主线程中,直接loop = asyncio.new_event_loop()
# 不能loop = asyncio.get_event_loop() 会触发RuntimeError: There is no current event loop in thread
因为asyncio程序中的每个线程都有自己的事件循环,但它只会在主线程中为你自动创建一个事件循环。所以如果你asyncio.get_event_loop在主线程中调用一次,它将自动创建一个循环对象并将其设置为默认值,但是如果你在一个子线程中再次调用它,你会得到这个错误。相反,您需要在线程启动时显式创建/设置事件循环:
loop = asyncio.new_event_loop()
asyncio.set_event_loop(loop)
在Django单个视图中使用asyncio实例代码如下(有多个IO任务时)
from django.views import View import asyncio import time from django.http import JsonResponse class TestAsyncioView(View): def get(self, request, *args, **kwargs): """ 利用asyncio和async await关键字(python3.5之前使用yield)实现协程 """ self.id = 5 start_time = time.time() ''' # 同步执行 # results = [self.io_task1(self.id), # self.io_task2(self.id), # self.io_task2(self.id)] ''' loop = asyncio.new_event_loop() # 或 loop = asyncio.SelectorEventLoop() asyncio.set_event_loop(loop) self.loop = loop works = [ asyncio.ensure_future(self.io_task3(5)), asyncio.ensure_future(self.io_task3(5)), asyncio.ensure_future(self.io_task3(5)), asyncio.ensure_future(self.io_task3(5)), asyncio.ensure_future(self.io_task3(5)), ] try: results = loop.run_until_complete(asyncio.gather(*works)) # 两种写法 # results = loop.run_until_complete(self.gather_tasks()) finally: loop.close() end_time = time.time() return JsonResponse({'results': results, 'cost_time': (end_time - start_time)}) async def gather_tasks(self): tasks = ( self.make_future(self.io_task1, self.id), self.make_future(self.io_task2, self.id), self.make_future(self.io_task2, self.id), self.make_future(self.io_task1, self.id), self.make_future(self.io_task2, self.id), self.make_future(self.io_task2, self.id), ) results = await asyncio.gather(*tasks) return results async def make_future(self, func, *args): future = self.loop.run_in_executor(None, func, *args) response = await future return response def io_task1(self, sleep_time): time.sleep(sleep_time) return 66 def io_task2(self, sleep_time): time.sleep(sleep_time) return 77 async def io_task3(self, sleep_time): # await asyncio.sleep(sleep_time) s = await self.do(sleep_time) return s async def do(self, sleep_time): await asyncio.sleep(sleep_time) return 66
在Django单个视图中使用ThreadPoolExecutor实例代码如下(有多个IO任务时)
from django.views import View import time from concurrent.futures import ThreadPoolExecutor, as_completed class TestThreadView(View): def get(self, request, *args, **kargs): start_time = time.time() future_set = set() tasks = (self.io_task1, self.io_task2, self.io_task2, self.io_task1, self.io_task2, self.io_task2) with ThreadPoolExecutor(len(tasks)) as executor: for task in tasks: future = executor.submit(task, 5) future_set.add(future) for future in as_completed(future_set): error = future.exception() if error is not None: raise error results = self.get_results(future_set) end_time = time.time() return JsonResponse({'results': results, 'cost_time': (end_time - start_time)}) def get_results(self, future_set): results = [] for future in future_set: results.append(future.result()) return results def io_task1(self, sleep_time): time.sleep(sleep_time) return 66 def io_task2(self, sleep_time): time.sleep(sleep_time) return 77
以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持自学编程网。
- 本文固定链接: https://www.zxbcw.cn/post/197252/
- 转载请注明:必须在正文中标注并保留原文链接
- QQ群: PHP高手阵营官方总群(344148542)
- QQ群: Yii2.0开发(304864863)