首页 > 编程语言 > 基于python爬取梨视频实现过程解析
2020
11-08

基于python爬取梨视频实现过程解析

目标网址:梨视频

然后我们找到科技这一页:https://www.pearvideo.com/category_8。其实你要哪一页都行,你喜欢就行。嘿嘿…

这是动态网站,所以咱们直奔network 然后去到XHR:


找规律,这个应该不难,我就直接贴网址上来咯,想要锻炼的可以找找看哈:

https://www.pearvideo.com/category_loading.jsp?reqType=5&categoryId=8&start=0

这个就是我们要找的目标网址啦,后面的0就代表页数,让打开这个网页发现是静态网页,这最好搞啦,直接上:


代码如下:

import requests
import parsel,re
import os
target = "https://www.pearvideo.com/videoStatus.jsp?contId="

url = "https://www.pearvideo.com/category_loading.jsp?reqType=5&categoryId=9&start=0"
res = requests.get(url)
res.encoding="utf-8"
html = parsel.Selector(res.text)
lists = html.xpath('/html/body/li/div/a/@href').getall()
for each in lists:

  print("https://www.pearvideo.com/"+each)

output;
https://www.pearvideo.com/video_1703486
https://www.pearvideo.com/video_1703189
https://www.pearvideo.com/video_1703161
https://www.pearvideo.com/video_1702880
https://www.pearvideo.com/video_1702773
...

顺利拿到,然后进入播放页面,却发现找不到MP4视频,怎么办?经过我一番努力(扯掉了几十根头发后)发现,它在另外一个网址里面


咋办?当然要想办法把这个网址搞到手啦,仔细分析下,发现这个网址非常陌生呀,唯一稍微熟悉点的就是那串数字了,前面我们拿到播放页的网址后面那串数字和这个对比,完全是一模一样的,这样的话那就好搞了,咱们直接用拼接的方式把它接上去就可以了,看代码:

for each in lists:
  url_num = each.replace('video_',"")
  urls = target+url_num
  print(urls)
``

```python
output:
https://www.pearvideo.com/videoStatus.jsp?contId=1703486
https://www.pearvideo.com/videoStatus.jsp?contId=1703189
https://www.pearvideo.com/videoStatus.jsp?contId=1703161
https://www.pearvideo.com/videoStatus.jsp?contId=1702880
https://www.pearvideo.com/videoStatus.jsp?contId=1702773
https://www.pearvideo.com/videoStatus.jsp?contId=1702633
...

出来了,好像稍微有点不一样,后面那啥&mrd=***************** 没有,怎么办?没有就不要呗,看过我发的百度图片那篇的朋友都懂,网址里面有些东西是不需要的,纯粹是搞咱们这些玩爬虫的,恶心咱们。不过没办法,毕竟是咱们要去爬人家的数据的。

网址问题解决了,但是点进去一看,发现这东东:

恩,很明显,是遇到反爬机制了,这个好搞,要什么给什么就行,代码如下:

	headers = {
  'User-Agent': 'Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.111 Safari/537.36',
  'Referer': 'https://www.pearvideo.com/video_'+ str(url_num)
  }
  html = requests.get(urls,headers=headers).text
  print(html)


搞定!!

最后我们看一下MP4能不能播放:


西八!404!!恩,这里就稍微有点麻烦了,还得找数据,把里面的时间戳改成 ‘cont-数字‘,感觉写了好多,手都有点累了,我就直接上代码了:

import requests
import parsel,re
import os


 
target = "https://www.pearvideo.com/videoStatus.jsp?contId="

url = "https://www.pearvideo.com/category_loading.jsp?reqType=5&categoryId=9&start=0"
res = requests.get(url)
res.encoding="utf-8"
html = parsel.Selector(res.text)
lists = html.xpath('/html/body/li/div/a/@href').getall()
# print(lists[2:])
# 提取视频后面的数字,数字是最重要的,需要传给 Referer 和 urls
for each in lists:
  url_num = each.replace('video_',"")
  urls = target+url_num
  # print(urls)
  headers = {
  'User-Agent': 'Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.111 Safari/537.36',
  'Referer': 'https://www.pearvideo.com/video_'+ str(url_num)
  }
  html = requests.get(urls,headers=headers).text
  
  cont = 'cont-' + str(url_num)

  # 提取 mp4 视频
  srcUrl = re.findall(f'"srcUrl":"(.*?)"',html)[0]
  # 替换视频里面的时间戳,改为可以真正播放的数据
  new_url = srcUrl.replace(srcUrl.split("-")[0].split("/")[-1],cont)
  print(new_url)
  

  # 使用视频后缀当视频名称
  filename = srcUrl.split("/")[-1]

  # 保存到本地
  with open("./images/"+filename,"wb") as f:
    f.write(requests.get(new_url).content)

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